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ksb
 Post subject: Coordinate Geometry : Equation of Circle
PostPosted: Wed Jul 28, 2010 12:47 pm 
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Question

What is the equation of a circle of radius 6 units centered at (3, 2)?
x^2 + y^2 + 6x – 4y = 23
x^2 + y^2 - 6x + 4y = 23
x^2 + y^2 + 6x + 4y = 23
x^2 + y^2 - 6x – 4y = - 23
x^2 + y^2 - 6x – 4y = 23

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shreyas
 Post subject: Re: Coordinate Geometry : Equation of Circle
PostPosted: Wed Aug 04, 2010 10:54 am 
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Joined: Sun Dec 18, 2005 9:50 am
Posts: 66
For a circle with center (a, b) and radius r, the equation is (x-a)^2 + (y-b)^2 = r^2.

In this case, (x - 3)^2 + (y - 2)^2 = 6^2

Simplifying, x^2 + y^2 - 6x -4y = 23

Answer: (E)
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