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vikas_gupta
 Post subject: HCF
PostPosted: Tue Oct 13, 2009 4:55 am 
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Joined: Tue Sep 29, 2009 12:12 pm
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HCF of 8(x2 -5x+6) and 12(x2-9)
where x has a exponent of 2
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shreyas
 Post subject: Re: HCF
PostPosted: Thu Oct 15, 2009 7:34 am 
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8(x^2 -5x+6) and 12(x^2-9)

8(x^2 -5x+6) = 4*2*(x-3)(x-2)
12(x^2-9) = 4*3*(x+3)(x-3)

The largest term that can divide both polynomials given here is 4(x-3), which is the HCF/GCD
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