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Considering first condition only, xyz>0 implies one of the following,
x is negative,y is negative,z is positive. OR
x is negative,y is positive,z is negative. OR
x is positive,y is negative,z is negative.
Nothing can be said about the sign of x/y,since x and y can be either positive or negative.
Considering second condition only,(x^2*y^2)/z=-8
That implies,z is negative since square of any real number can never be negative.
Again nothing can be said about the sign of x/y.
However,if consider both conditions,that is,z is negative,
then x and have have different signs and thus x/y is always negative.
Ans- E(Both statements together are sufficient)
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