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 Post subject: Numbers + Probbability
PostPosted: Wed Feb 20, 2008 3:26 pm 
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Joined: Wed Jan 02, 2008 7:52 am
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If n is an integer from 1 to 96, what is the probability for n*(n+1)*(n+2) being divisible by 8?

Solve this if you can...


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PostPosted: Wed Apr 23, 2008 11:55 am 
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Location: Chennai, India
Whenever 'n' is even, the product n * (n+2) will be divisible by 8 as one of the two numbers n or n + 2 will be divisible by 4 and the other by 2.

That gives 48 numbers in the set 1 to 96.

Plus when (n + 1) = 8, the number will be divisible by 8. there are 12 multiples of 8 in the set 1 to 96. So, there are 12 values that 'n' can take where n + 1 is divisible by 8. And in all these cases 'n' will be odd. So, there is no element common in this 12 and the earlier 48.

So, a total 60 values out of 96.

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