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 Post subject: QOTW : Number Theory DS
PostPosted: Fri Apr 17, 2009 10:50 am 
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Joined: Tue Dec 28, 2004 2:34 am
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Question

Is ab positive?
(1) (a+b)^2 < (a-b)^2
(2) a = b

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 Post subject: Re: QOTW : Number Theory DS
PostPosted: Thu Apr 23, 2009 11:43 am 
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Joined: Tue Dec 28, 2004 2:34 am
Posts: 79
Location: Chennai, India
Correct Answer is A. Statement 1 alone is sufficient, while statement 2 is not.

It is an "Is" question. So, the answer has to be a definite YES or a definite NO. It cannot be a MAYBE.

Let us evaluate statement 1.
Expanding both sides of the inequality, we get a^2 + b^2 + 2ab < a^2 + b^2 - 2ab
Simplifying we get, 4ab < 0 or ab < 0.
So, we can convincingly answer that ab is not positive. So, statement 1 is sufficient to answer the question.

The correct answer is either A or D.

Now let us evaluate the statement 2. This is actually the statement that could trick you.
a = b.
So, either both a and b or positive or both a and b are negative. In either case ab is positive.
We will certainly be "tempted" to decide that statement 2 is also sufficient.
The catch is that, both a and b could be 0. In that case ab = 0, which is not positive.
As we are not able to conclude if ab is positive or not with statement 2, it is not sufficient.

So, choice A is the correct answer.

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ACE GMAT Quant with 4GMAT's Advanced Math Lesson Books, eBooks.
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 Post subject: Re: QOTW : Number Theory DS
PostPosted: Tue Sep 29, 2009 4:54 am 
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Joined: Mon Sep 14, 2009 9:12 am
Posts: 16
Great Explanation. Even i thought Statement 2 alone is also sufficient.

a = b.

So a and b are both positive numbers or negative numbers hence product is always postive.

But this fails when a=0 -> b=0, product ab=0 is not positive.

Hence Statement 1 alone is sufficient.


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