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 Post subject: Roots of Quadratic Equation
PostPosted: Mon Feb 22, 2010 5:21 am 
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The roots of the quadratic equation x^2 - ax + b = 0 are both integers. If 'b' is a prime number and 'a' is a positive integer, which of the following could be the value of the sum of the roots of the quadratic equation?

(A) 24
(B) 29
(C) 57
(D) 40
(E) 92


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Mon Feb 22, 2010 7:13 pm 
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Ooh. That got me thinking.

Well the answer is 92.
Here's how I went about it.
Since the equation has 2 roots and both are integers,
Sum of roots of a quadratic ax2 + bx + c = 0 is -b/a.
And b2 -4ac = 0
So in this case : Sum of roots = a.
and a2 = 4b.
Now start checking the options.
Since a2 has to be a multiple of 4, we can eliminate B and C.

Now try out A,D, E. Only E gives the value of b as a prime number 23.

Regards,
VP


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Wed Feb 24, 2010 11:53 am 
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Hi Vinodparam,

I do not get the solution. Why should b^2 be equal to 4ac? Am I missing something here?


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Tue Mar 02, 2010 4:30 am 
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Since 'b' is a prime number and 'a' is a positive integer, the sum of the roots (= a) and the product of the roots (= b) are both integers.

b is prime => product of roots = b*1
=> Sum of roots = (b+1).

So, the sum of the roots must be one more than a prime number.

24 (= 23 + 1) is the required number.

Answer: A


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Thu Mar 18, 2010 6:35 am 
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Shreyas i didnt get that.. how did u conclude that the sum of the roots and the prod of the roots?? can u brief??


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Sat Mar 20, 2010 6:47 am 
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For a quadratic equation of the form ax^2 + bx + c = 0,
Sum of the roots (SOR) = -b/a; product of the roots (POR) = c/a.

For the equation x^2 - ax + b = 0, SOR = -(-a)/1 = a, POR = b/1 = b.

Hope its clear.


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Mon Mar 29, 2010 5:47 am 
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Shreyas,

Thanks for that explanation on SOR and POR. I was aware of that.. just had a smal confusion on this part mentioned below:

b is prime => product of roots = b*1
=> Sum of roots = (b+1).

So, the sum of the roots must be one more than a prime number.

24 (= 23 + 1) is the required number.


Ok. Since the only option from the given answer choice (24) staisfies this criteria of (Sum of the roots +1) u chose 24 as the answer rite? Just wanted to confirm that..
Since any prime number has to be a multiple of 1 and itself..(this one struck me a little later)


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 Post subject: Re: Roots of Quadratic Equation
PostPosted: Thu Apr 01, 2010 7:02 am 
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Yes. 24 is the only number (out of the 5 choices) that fits the case.


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